Answer:
\(x=\dfrac{17}{4}\)
.
Step-by-step explanation:
It is given that ABCD is an isosceles trapezoid and it has diagonals AC = 10x + 7 and BD = 2x + 41.
We need to find the value of x.
We know that the diagonals of an isosceles trapezoid are equal.
\(AC=BD\)
\(10x+7=2x+41\)
\(10x-2x=41-7\)
\(8x=34\)
\(x=\dfrac{34}{8}\)
\(x=\dfrac{17}{4}\)
Hence the value of x is \(\dfrac{17}{4}\).
