The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground? Given: g = -9.8 meters/second2
(9.8m/s) divided by 4m. the m's cancel out leaving you with s so 2.45s
Answer:
The time is 0.90 sec.
Explanation:
Given that,
Height = 4.00 m
We need to calculate the time
Using equation of motion
\(s = ut+\dfrac{1}{2}gt^2\)
Where, s = height
g = acceleration due to gravity
t = time
Put the value into the formula
\(4.00=0+\dfrac{1}{2}\times9.8\times t^2\)
\(t^2=\dfrac{4.00\times2}{9.8}\)
\(t=\sqrt{\dfrac{4.00\times2}{9.8}}\)
\(t=0.90\ sec\)
Hence, The time is 0.90 sec.