Answered

A running track in the shape of an oval is shown. The ends of the track form semicircles.



What is the perimeter of the inside of the track?


(π = 3.14)


A - 392.00 m

A - 372.22 m

A - 444.44 m

A - 588.88 m


P.S. I attached a file here to look at the oval.

A running track in the shape of an oval is shown. The ends of the track form semicircles. What is the perimeter of the inside of the track? (π = 3.14) A - 392.0 class=

Verified Answer :

I would think 444.44 ._. Do you go to FLVS? ;-; cause im on the test to xD

calculista

Answer:

The perimeter of inside of the track is \(444.44\ m\)

Step-by-step explanation:

we know that

The perimeter of the oval is equal to the circumference of a circle (two semicircles is equal to one circle) plus the length of \(150\ m\) multiplied by \(2\)

Find the circumference of a circle

The circumference of a circle is equal to

\(C=\pi D\)

we have

\(D=46\ m\)

substitute the values

\(C=(3.14)(46)=144.44\ m\)

Find the perimeter of the oval

\(144.44\ m+2*150\ m=444.44\ m\)

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