Answered

A coil 4.20 cm radius, containing 470 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×10 −2 T/s )t+(2.55×10 −5 T/s4 )t4. The coil is connected to a 580-Ω resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil.

A)

Find the magnitude of the induced emf in the coil as a function of time.

B)

What is the current in the resistor at time t0 = 4.50 s ?

Verified Answer :

so, b=(n/l)I
n=470
l=0.042
I=v/r

so it becomes
v(t)=BR/(470/0.042)

also, v=emf with no current so it becomes
EMF(t)=BR/(470/0.042)

you can plug the b values in to solve the emf. B=( 1.20×10 −2 T/s )t+(2.55×10 −5 T/s4 )t4

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