A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s2, what is the radius of the circle?


0.60 m

1.2 m

0.36 m

0.84 m

Verified Answer :

I googled it and I think the answer is 0.60m


good luck!

By definition, the centripetal acceleration is given by:


\(a = \frac{v^2}{r}
\)

Where,

v: tangential speed

r: radius of the circular path

Clearing the radio we have:

\(r = \frac{v^2}{a}
\)

Substituting values we have:

\(r =\frac{0.51 ^ 2}{0.43}

r = 0.6 m
\)

Therefore, the radius of the circular path is equal to 0.60 meters.

Answer:

The radius of the circle is:

0.60 m

option1