An ant crawls at a rate of 2 1/6 feet per minute.

At this rate, how long does it take the ant to crawl a distance of 5 1/5 feet?

Enter your answer as a mixed number in simplest form in the box.

Verified Answer :

Answer:

\(2\frac{2}{5}\ minutes\)

Step-by-step explanation:

Convert mixed number to an improper fractions first

\(2\frac{1}{6}\frac{ft}{min}=\frac{2*6+1}{6}=\frac{13}{6}\frac{ft}{min}\)

\(5\frac{1}{5}\ ft=\frac{5*5+1}{5}=\frac{26}{5}\ ft\)

By proportion

\(\frac{(13/6)}{1}\frac{ft}{min} =\frac{(26/5)}{x}\frac{ft}{min}\\ \\ x=(26/5)/(13/6)\\ \\x=156/65\ min\)

Convert to mixed number

\(\frac{156}{65}\ min=\frac{130}{65}+\frac{26}{65}=2+\frac{26}{65}=2+\frac{2}{5} =2\frac{2}{5}\ min\)

The rate of speed is the rate at which the total distance is traveled in the time taken. The time taken by the ant to crawl a distance of  \(5\dfrac{1}{5}\) feet is  \(2\dfrac{2}{5}\) minutes.

What is rate of speed?

The rate of speed is the rate at which the total distance is traveled in the time taken. Rate of speed can be given as,

\(s_r=\dfrac{x}{t}\)

Here, \(x\) is the distance traveled by the object and \(t\) is time taken but the object to cover that distance.

Given information-

The rate of speed of crawl of ant is \(2\dfrac{1}{6}\) feet per minute.

Total distance is \(5\dfrac{1}{5}\) feet.

As the total distance is \(5\dfrac{1}{5}\) feet and the rate of speed of the crawl of ant is \(2\dfrac{1}{6}\) . Hence the time can be calculated using above formula as,

\(s_r=\dfrac{x}{t}\)

Put the values,

\(2\dfrac{1}{6} =\dfrac{5\dfrac{1}{5} }{t}\)

\(\dfrac{13}{6} =\dfrac{\dfrac{26}{5} }{t}\)

Solve for \(t\),

\(t=\dfrac{26}{5} \times\dfrac{13}{6} \\t=\dfrac{26}{5}\\t=2\dfrac{2}{5}\)

Hence the time taken by the ant to crawl a distance of \(5\dfrac{1}{5}\) feet is \(2\dfrac{2}{5}\) minutes.

Learn more about the rate of speed here;

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