Lesson 8: Systems of Equations and Inequalities Unit Test CE 2015

Algebra 1 Unit 7: Systems of Equations and Inequalities

Lesson 8: Systems of Equations and Inequalities Unit Test CE 2015 Algebra 1 Unit 7: Systems of Equations and Inequalities class=
Lesson 8: Systems of Equations and Inequalities Unit Test CE 2015 Algebra 1 Unit 7: Systems of Equations and Inequalities class=
Lesson 8: Systems of Equations and Inequalities Unit Test CE 2015 Algebra 1 Unit 7: Systems of Equations and Inequalities class=
Lesson 8: Systems of Equations and Inequalities Unit Test CE 2015 Algebra 1 Unit 7: Systems of Equations and Inequalities class=

Verified Answer :

Answer:

We are asked to find which graph represents the solution of the given system of equations:

\(y=-x+2------------(1)\)

and \(y=3x-1-------------(2)\)

We find the intersection point of the two equations by solving these system of equations using elimination method as:

subtract equation (2) from equation (1) to obtain:

\(0=-4x+3\)

\(3=4x\)

\(x=\dfrac{3}{4}=0.75\)

Also putting this value of x in equation (1) we get:

\(y=-\dfrac{3}{4}+2\\\\y=\dfrac{-3+4\times 2}{4}\\\\y=\dfrac{-3+8}{4}\\\\y=\dfrac{5}{4}=1.25\)

Hence, the intersection point is:  (0.75,1.25).

Hence the graph that represents the solution of the system of given linear equations is attached to the answer.

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