Answer:
Angular frequency, \(\omega=6.52\ rad/s\)
Explanation:
Given that,
Amplitude of simple harmonic motion, A = 2.3 m
Maximum velocity of the object, \(v_{max}=15\ m/s\)
To find,
The object's angular frequency.
Solution,
The equation of the displacement of particle is given by :
\(y=A\ cos(\omega t)\)
On differentiating above equation, we get the expression for maximum velocity as :
\(v_{max}=A\times \omega\)
\(\omega=\dfrac{v_{max}}{A}\)
\(\omega=\dfrac{15\ m/s}{2.3\ m}\)
\(\omega=6.52\ rad/s\)
So, the angular frequency of the object is 6.52 rad/s.
