The factored form of 4a3b5 − 16a5b2 + 12a2b3
Answer:
\(4a^2b^2(ab^3 -4a^3+3b)\)
Step-by-step explanation:
Given : \(4a^3b^5 -16a^5b^2+12a^2b^3\)
To Find: Find factored form.
Solution:
\(4a^3b^5 -16a^5b^2+12a^2b^3\)
Take 4 as common
\(4(a^3b^5 -4a^5b^2+3a^2b^3)\)
Now take \(a^2\) as common
\(4a^2(ab^5 -4a^3b^2+3b^3)\)
Now take \(b^2\) as common
\(4a^2b^2(ab^3 -4a^3+3b)\)
Hence The factored form of \(4a^3b^5 -16a^5b^2+12a^2b^3\) is \(4a^2b^2(ab^3 -4a^3+3b)\)