JCash829
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What is the net ionic equation for the reaction of solid iron with aqueous copper sulfate? (Hint: First use the activity series to write the formula unit equation!)

Verified Answer :

MissPhiladelphia

For the answer to the question above,
The reaction of solid iron with aqueous copper sulfate is an example of a single displacement type of reaction which exchanges only the cations of the element and the compound. In this case, the equation is 

Fe (s) + CuSO4 (aq) = FeSO4 + Cu (s) 

Answer:

The net ionic equation for the reaction of solid iron with aqueous copper sulfate:

\(Fe(s)+Cu^{2+}(aq)\rightarrow Fe^{2+}+(aq)+Cu(s)\)

Explanation:

Solid iron = Fe

Copper sulfate = \(CuSO_4\)

\(Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)\)

In an aqueous solution of copper sulfate we have copper (II) ions and sulfate ions.

\(CuSO_4(aq)\rightarrow Cu^{2+}(aq)+SO_4^{2-}(aq)\)

In an aqueous solution of ferrous sulfate we have ion (II) ions and sulfate ions.

\(FeSO_4(aq)\rightarrow Fe^{2+}+(aq)+SO_4^{2-}(aq)\)

\(Fe(s)+Cu^{2+}(aq)+SO_4^{2-}(aq)\rightarrow Fe^{2+}+(aq)+SO_4^{2-}(aq)+Fe^{2+}+(aq)\)

Cancelling out the common ions from both sides, we get the net ionic equation:

\(Fe(s)+Cu^{2+}(aq)\rightarrow Fe^{2+}+(aq)+Cu(s)\)

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