Verified Answer :
I believe that the answer to the question asked above is the following
sound intensity = sound power / (4 pi R2)
so if you decrease the intensity by a factor of 2 the sound wave will also decrease by a factor of 2.
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.
The amplitude of a sound wave must be decreased by a factor of √2
\(\texttt{ }\)
Further explanation
Let's recall the speed of wave and intensity of wave formula as follows:
\(\large {\boxed {v = \lambda f}}\)
f = frequency of wave ( Hz )
v = speed of wave ( m/s )
λ = wavelength ( m )
\(\texttt{ }\)
\(\large {\boxed {I = 2 \pi^2 A^2 f^2 \rho v}}\)
I = intensity of wave ( W/m² )
A = amplitude of wave ( m )
f = frequeny of wave ( Hz )
ρ = density of medium ( kg/m³ )
v = speed of wave ( m/s )
Let's tackle the problem!
\(\texttt{ }\)
Given:
Amplitude of First Wave = A
Intensity of First Wave = I
Intensity of Second Wave = ¹/₂ I
Asked:
Amplitude of Second Wave = ?
Solution:
\(I : I' = 2 \pi^2 A^2 f^2 \rho v : 2 \pi^2 (A')^2 f^2 \rho v\)
\(I : I' = A^2 : (A')^2\)
\(I : \frac{1}{2}I = A^2 : (A')^2\)
\(2 : 1 = A^2 : (A')^2\)
\(2(A')^2 = A^2\)
\((A')^2 = \frac{1}{2}A^2\)
\(A' = \frac{A}{\sqrt{2}}\)
\(\texttt{ }\)
Conclusion:
The amplitude of a sound wave must be decreased by a factor of √2
\(\texttt{ }\)
Learn more
- Doppler Effect : https://brainly.com/question/3841958
- Example of Doppler Effect : https://brainly.com/question/810552
- Sound Waves Cannot Travel In Space. : https://brainly.com/question/546436
- Frequency of The Beats - Doppler Effect : https://brainly.com/question/12367463
\(\texttt{ }\)
Answer details
Grade: College
Subject: Physics
Chapter: Sound Waves
\(\texttt{ }\)
Keywords: Sound, Wave , Wavelength , Doppler , Effect , Policeman , Stationary , Frequency , Speed , Beats, Medium, Space