Answer: \(0.02130\times 10^{-17}Joules\)
Explanation:
\(E=\frac{hc}{\lambda}\)
E= energy
h = Planck's constant = \(6.626\times 10^{-34}Js\)
c = speed of light =\(3\times 10^8ms^{-1}\)
\(\lambda\) = Wavelength of radiation = 933 nm =\(933\times 10^{-9}m\)
Now put all the given values in this formula, we get
\(E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8ms^{-1}}{933\times 10^{-9}m}\)
\(E=0.02130\times 10^{-17}Joules\)
Thus energy of a 933 nm wave is \(0.02130\times 10^{-17}Joules\)
