ok so some basic rules
\((x^m)(x^n)=x^{m+n}\)
\((ab)^c=(a^c)(b^c)\)
\((x^m)^n=x^{mn}\)
\(x^0=1\)
\(x^{-m}= \frac{1}{x^m}\)
so
\([(3y^0x^2)^6][y^{-3}zx^8]\)
\([(3(1)x^2)^6][y^{-3}zx^8]\)
\([(3x^2)^6][y^{-3}zx^8]\)
\([(3^6)((x^2)^6)][y^{-3}zx^8]\)
\([(3^6)(x^{12})][y^{-3}zx^8]\)
\((3^6)(x^{12})(y^{-3})(z)(x^8)\)
\((3^6)(x^{12})(x^8)(y^{-3})(z)\)
\((3^6)(x^{20})(\frac{1}{y^3})(z)\)
\(\frac{3^6x^{20}z}{y^3}\)
\(\frac{729x^{20}z}{y^3}\)
