Verified Answer :

bugbug27

you find the slope of the equation using y2-y1/x2-x1 and then you find the y intercept which is the point that crosses the y axis. Then you put that information into the slope intercept equation (y=mx+b   m=slope b=y intercept)


at least i think thats what you are asking

PsychrolutesMarcidus

First you need the slope, which is easily attainable by the change of x over the change of y

ex. with coordinates (x,y)(X,Y)

m=slope
m=\(\frac{ rise}{run}\)
   =\(\frac{  change x}{ change of y}\)
   = \(\frac{X-x}{Y-y}\)

Then you will have every thing except the y intercept
 (represented by b)

Using the slope-intercept form 
and x and y being represented by the x, y values of a co-ordinate

y=mx+b
We can derive b

b= y-mx

Then when we have both m and b
Insert them into the form

ex. if m=-4, b=6

y=-4x+6

Taa daa!
If that helped please let me know 
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