Answer:
Factored form the given quadratic equation \(8y^2+6y+1\) is \((2y+1)(4y+1)\)
Step-by-step explanation:
Given : \(8y^2+6y+1\)
We have to factorize the given equation completely and place the factors in the proper location on the grid.
Consider the given quadratic equation \(8y^2+6y+1\).
We solve the given quadratic equation using middle term splitting method,
6y can be written as 4y + 2y , then equation becomes,
\(8y^2+6y+1=8y^2+4y+2y+1\)
Taking 4y common from first two term and 1 common from last two term , we have,
\(\Rightarrow 4y(2y+1)+1(2y+1)\)
\(\Rightarrow (2y+1)(4y+1)\)
Thus, factored form the given quadratic equation \(8y^2+6y+1\) is \((2y+1)(4y+1)\)
The placement of the factors in the proper location on the grid is shown in figure attached below.
