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sarahcaramel14 sarahcaramel14
  • 21-01-2017
  • Mathematics
Answered

What is the sum of the arithmetic sequence 8, 15, 22 …, if there are 26 terms?

Verified Answer :

bartdrinksmalk
bartdrinksmalk bartdrinksmalk
  • 21-01-2017

For the regular sequence 1, 2, 3, ..., \(n\), then sum is
\(\frac{n(n+1)}{2}\)

If we multiply each number by 7 (7, 14, 21, ...), then the sum is
\(\frac{7n(n+1)}{2}\)
and if we add 1 to each number (8, 15, 22, ...) then the sum is
\(\frac{7n(n+1)}{2}+n\)

We have \(n=26\) terms, so the sum is:
\(\frac{7(26)(27)}{2}+26\)
\(=7(13)(27)+26\)
\(=91(27)+26\)
\(=2457+26\)
\(=2483\)

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