The expression 1/2 (h) (b^1+b^2) gives the area of a trapezoid, with b^1 and b^2 representing the two base lengths of a trapezoid and h representing the height. Find the area of a trapezoid with base lengths 4 inches and 6 inches and a height of 8 inches.
We have
\(b_{1}=4\), \(b_{2}=6\), and \(h=8\)
The area is
\(\frac{1}{2}h(b_{1}+b_{2})\)
\(=\frac{1}{2}(8)(4+6)\)
\(=4(10)\)
\(=40\)
area = h [b1+b2]
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