Solve the system of equations.{y=2x−64x−2y=14{y=2x−64x−2y=14use the substitution method.the solution is (4, 14)(4, 14).the solution is (14, 4)(14, 4).there is no solution.there are an infinite number of solutions.
I did this test and failed. But when I reviewed it showed me the right answers... so here is the answer: C. There is no solution.
Answer:
Option C is correct.
No solutions
Step-by-step explanation:
Given the system of equation:
\(y =2x-6\) ....[1]
\(4x-2y=14\) .....[2]
Substitute equation [1] into [2] we get;
\(4x-2(2x-6)=14\)
Using distributive property: \(a \cdot (b+c) = a\cdot b+ a\cdot c\)
\(4x-4x+12=14\)
Combine like terms;
\(12=14\) False.
Therefore, there is no solution for the given system of the equations.