A box with a mass of 7 kilograms is pushed up a ramp to a height of 5 meters. what is the work done against the force of gravity? assume the ramp has negligible friction.
so work done = mgh = 7×10×5 = 350 joules
so answer is 350 joules !!
Answer: The work done by the ramp against the force of gravity is -343 J
Explanation:
Work is defined as the force that is causing the movement or displacement of an object.
Mathematically,
\(W=F\times d\)
We know that:
\(F=m\times g\)
where,
W = work done by the ramp = ?
m = mass of the box = 7 kg
g = acceleration due to gravity = \(-9.8m/s^2\) (Negative sign appears because it is acting against the gravity)
d = displacement = 5 m
Putting values in above equation, we get:
\(W=7kg\times (-9.8m/s^2)\times 5m\\\\W=-343J\)
Hence, the work done by the ramp against the force of gravity is -343 J