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sweetblondy4
sweetblondy4 sweetblondy4
  • 21-01-2017
  • Chemistry
Answered

The boiling point of an aqueous solution is 102.08 °C. What is the freezing point? Constants can be found here.

Verified Answer :

MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 31-01-2017

Colligative
properties calculations are used for this type of problem. Calculations are as
follows:



ΔT(freezing point)  = (Kf)(molality)

ΔT(freezing point)
= 1.86 °C kg / mol (molality)
 
Tf - 102.08 = 1.86m

Tf = 1.86m + 102.08

The concetration of the solution is needed in order to obtain a specific value.

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