Answer: \(24.5\times 10^{23}atoms\)
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number \(6.023\times 10^{23}\) of particles.
To calculate the number of moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar Mass}}=\frac{163g}{40g/mol}=4.075moles\)
1 mole of calcium contains = \(6.023\times 10^{23}atoms\)
Thus 4.075 moles of calcium contains = \(\frac{6.023\times 10^{23}}{1}\times 4.075 =24.5\times 10^{23}atoms\)
Thus there are \(24.5\times 10^{23}atoms\) in 163 g of calcium.
