Answer:
\(\text{The point slope form is }y+3=\frac{1}{2}(x-6)\)
Step-by-step explanation:
\(\text{Given that the line line passes through the point (6,-3) and has slope }\frac{1}{2}\)
we have to find the equation of line in the point-slope form.
\(\text{The equation of line passing through the point (x',y') and has slope m is }\)
\(y-y'=m(x-x')\)
\(\text{Passing point=(x',y')=(6,-3)}\)
\(Slope=m=\frac{1}{2}\)
The equation is
\(y-(-3)=\frac{1}{2}(x-6)\)
\(y+3=\frac{1}{2}(x-6)\)
which is required point-slope form.
Option 3 is correct.
