Answer:
Option C is correct.
Step-by-step explanation:
Given two numbers
\(10\times 10^9\text{ and } 99\times 10^6\)
we have to estimate about many times a number larger than another.
To estimate we have to divide.
\(\frac{10\times 10^9}{99\times 10^6}\) → (1)
As \(\frac{x^a}{x^b}=x^{a-b}\)
Equation (1) implies
\(\frac{10\times 10^{9-6}}{99}\)
⇒ \(\frac{10\times 10^3}{99}\)
⇒ \(\frac{10000}{99}=101.01\sim 100\thinspace times\)
Hence, 100 times larger.
Option C is correct.
