When 10.00 ml of 1.00 m hcl solution is mixed with 115 ml of 0.100 m naoh solution in a constant-pressure calorimeter, the temperature rises from 22.45 °c to 23.25 °

Ccalculate q for this reaction, assuming that the heat capacity of the calorimeter is the same as that of 125 g of water.?

Verified Answer :

We can use the formula
q = m cp ΔT
The
cp of water is 4.18 J/g K

q = 125 (4.18) (23.25 - 22.45)
q = 418 J

The heat evolved for the neutralization reaction is equal to 418 J.

The amount of energy required by the reaction is \(\boxed{418\,{\text{J}}}\) .


Further Explanation:


Given:

The volume of \(HCl\)  mixed in the calorimeter is \(10.0\,{\text{ml}}\) .

The volume of \(NaOH\)  mixed in the calorimeter is \(115\,{\text{ml}}\) .

The initial temperature of the solution is \({22.45\:^{\circ}\text{C}}\)  or \(295.6\,{\text{K}}\) .

The final temperature of the solution is \({23.25\:^{\circ}\text{C}}\)  or \(296.4\,{\text{K}}\) .

The specific heat capacity of water is \(4.18\,{{\text{J}}\mathord{\left/{\vphantom{{\text{J}}{{\text{g}}\cdot{\text{K}}}}}\right.\kern- ulldelimiterspace}{{\text{g}}\cdot{\text{K}}}}\) .


Concept:

The total volume of the calorimeter after the addition of  \(HCl\) and \(NaOH\)  is:

\(\begin{aligned}V&=115+10\\&=125\,{\text{ml}}\\\end{aligned}\)


The density of the given solution is \(1\,{{\text{g}}\mathord{\left/{\vphantom{{\text{g}}{{\text{ml}}}}}\right.\kern- ulldelimiterspace}{{\text{ml}}}}\) . Therefore, the mass of the solution is:

\(\begin{aligned}m&={\text{density}}\times{\text{volume}}\\&=1\,{{\text{g}}\mathord{\left/{\vphantom{{\text{g}}{{\text{ml}}}}}\right.\kern- ulldelimiterspace}{{\text{ml}}}}\times125\,{\text{ml}}\\&=125\,{\text{g}}\\\end{aligned}\)


The change in temperature of the calorimeter is.

\(\begin{aligned}\Delta T&={T_f}-{T_i}\\&=296.4-295.6\\&=0.8\\\end{aligned}\)


Now, the amount of heat absorbed by the calorimeter to complete the reaction is given as:

\(q=m\times C\times\Delta T\)


Here,  \(q\) is the amount of heat required for the reaction and \(C\)  is the heat capacity of the calorimeter.


Substitute the values in the above expression.

\(\begin{aligned}q&=125\times4.18\times0.8\\&=125\times3.344\\&=418\,{\text{J}}\\\end{aligned}\)

Thus, the amount of energy required by the reaction is \(\boxed{418\,{\text{J}}}\) .


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Answer Details:

Grade: High School

Subject: Physics

Chapter: Heat and Thermodynamics


Keywords:

10 ml of 1.00 m HCl, 115 ml of 0.100 m NaOH, constant pressure, calorimeter, heat capacity, same as 125g of water, temperature rises, energy required.