The magnitude of the force between the objects will be four times the initial force.
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Further explanation
Electric charge consists of two types i.e. positively electric charge and negatively electric charge.
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There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :
\(\large {\boxed {F = k \frac{Q_1Q_2}{R^2} } }\)
F = electric force (N)
k = electric constant (N m² / C²)
q = electric charge (C)
r = distance between charges (m)
The value of k in a vacuum = 9 x 10⁹ (N m² / C²)
Let's tackle the problem now !
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Given:
initial force between objects = F
initial charge of the object = q
final charge of the object = 2q
Unknown:
final force between objects = F' = ?
Solution:
\(F : F' = k \frac{q_1 q_2}{(d)^2} : k \frac{q'_1 q'_2}{(d')^2}\)
\(F : F' = k \frac{q_1 q_2}{(d)^2} : k \frac{2q_1 (2q_2)}{(d)^2}\)
\(F : F' = (q_1 q_2) : (4q_1 q_2)\)
\(F : F' = 1 : 4\)
\(F' = 4F\)
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Conclusion:
The magnitude of the force between the objects will be four times the initial force.
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Learn more
- The three resistors : https://brainly.com/question/9503202
- A series circuit : https://brainly.com/question/1518810
- Compare and contrast a series and parallel circuit : https://brainly.com/question/539204
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Answer details
Grade: High School
Subject: Physics
Chapter: Static Electricity
