Answer:
\(0.86\times 10^{10} Hz\)
Explanation:
Given that, the wavelength of the microwave radiation is,
\(\lambda=3.5 cm=3.5\times 10^{-2}m\)
And as we know that the speed of the wave is,
\(v=3\times 10^{8}m/s\)
Now the frequency of the microwave radiation can be calculated as
\(f=\frac{v}{\lambda}\)
Here, f is the frequency of microwave signal, v is the speed of the signal and \(\lambda\) is the wavelength of signal.
Now put all the given variable in above equation.
\(f=\frac{3\times 10^{8}m/s}{3.5\times 10^{-2}m } \\f=0.86\times 10^{10} Hz\)
This the required frequency.
