The Sierpinski Triangle is a type of progression where an equilateral triangle has 1/4 of its area removed to create a new shape. A series of these triangles is shown below, starting with an area of 64. If we remove 1/4 of the area what fraction of the area remains?
The Sierpinski Triangle is a type of progression where an equilateral triangle has 1/4 of its area removed to create a new shape.
starting with an area of 64. If we remove 1/4 of the area
so the removed area = 64* ( 1/4) = 16
remaining area = 64 - 16 = 48
fraction of the remaining area = 48 / 64 = 3/4
or another way 1 - 1/4 = 3/4
The fraction of the area that remains should be \(\frac{3}{4}\)
Since an equilateral triangle has 1/4 of its area removed to create a new shape. A series of these triangles is shown below, starting with an area of 64.
Now the removed area should be
\(= 64\times ( 1/4)\)
= 16
So, remaining area = 64 - 16 = 48
Now
fraction of the remaining area \(= 48 / 64 = 3/4\)
Therefore, The fraction of the area that remains should be \(\frac{3}{4}\)
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