Answer:
\(2.91\times 10^{15}\)
Step-by-step explanation:
Since, an earthquake has a Richter scale magnitude,
\(M=log(\frac{I}{I_0})\)
Where, I is the intensity of the earthquake,
While, \(I_0\) is the reference intensity,
Given, M = 5.6,
And, \(I_0=7.3 \times 10^9\)
\(\implies 5.6 = log(\frac{I}{7.3 \times 10^9})\)
\(5.6=log I - log(7.3\times 10^9)\) ( Because, log (a/b) = log a - log b ),
\(5.6 = log I - 9.86332286012\)
\(log I = 15.4633228601\)
\(\implies I=10^{15.4633228601}=2.9061823449\times 10^{15}\approx 2.91\times 10^{15}\)
Hence, the intensity of the earthquake is \(2.91\times 10^{15}\).
