V3+ find the number of protons and electrons
Explanation:
Atomic number of Vanadium is 23 and its electronic distribution is 2, 8, 8, 5. And, we know that when an atom has a positive charge then it means electrons have been lost by the atom.
As the given Vanadium atom has a charge of +3 which means that 3 electrons have been lost by Vanadium. Hence, electronic configuration of Vanadium in both neutral and ionic form are as follows.
Neutral state: \([Ar]4s^{2} 3d^{3}\)
Ionic state (\(V^{3+}\)): \([Ar]4s^{0} 3d^{2}\)
When an atom is neutral then its number of protons is equal to the number of electrons.
Hence, we can conclude that in \(V^{3+}\) number of protons is 23 and number of electrons is 20.