a force of 200 N to. the left and another force of 50 N to the left
If you want to calculate the net force, then it would be:
Fnet = 200 + 50 [ as the directions are same, that's why we are adding ]
Fnet = 250 N [ towards left ]
In short, Your Answer would be 250 N towards left
Hope this helps!
The net force applied to the object is 250 N.
"Your question is not complete, it seems to be missing the following information";
find the net force applied to the object
The given parameters;
The net force applied to the object is sum of the forces acting on the object in the same direction.
∑Fₓ = F₁ + F₂
∑Fₓ = 200 N + 50 N
∑Fₓ = 250 N
Thus, the net force applied to the object is 250 N.
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