bobmarly76
Answered

When an aqueous solution at room temperature is analyzed, the [H+] is found to be 2.0 × 10−3 M. What is the [OH−]?

A5.0 × 10−12 M
B2.0 × 10−11 M
C4.0 × 10−6 M
D5.0 × 10−11 M

Verified Answer :

dylanfrench456

the answer would be A. 5.0x10-12m

Answer : The correct option is, (A) \(5.0\times 10^{-12}M\)

Explanation:

First we have to calculate the pH.

\(pH=-\log [H^+]\)

\(pH=-\log (2.0\times 10^{-3})\)

\(pH=2.69\)

Now we have to calculate the pOH.

\(pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-2.69=11.31\)

Now we have to calculate the \(OH^-\) concentration.

\(pOH=-\log [OH^-]\)

\(11.31=-\log [OH^-]\)

\([OH^-]=5.0\times 10^{-12}M\)

Therefore, the \(OH^-\) concentration is, \(5.0\times 10^{-12}M\)

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