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Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.


A.) x = 0, solution is not extraneous

B.) x = 0, solution is extraneous

C.) x = 12, solution is not extraneous

D.) x = 12, solution is extraneous

Verified Answer :

Answer:

D.) x = 12, solution is extraneous

Step-by-step explanation:

We are given a equation

     \(-4\times \sqrt{x-3}=12\)

⇒     \(\sqrt{x-3}=-3\)

 on squaring both sides, we get

           x-3=9

    ⇒  x=12

     Putting x=12 in original equation gives

        \(-4\times \sqrt{12-3}=12\)

⇒            -4×3=12

which is not true

Hence, correct option is:

D.) x = 12solution is extraneous

Answer:

x = 12, solution is extraneous

Step-by-step explanation:

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