If f(x) = 3x + 3, g(x) = 3x + 3, and h(x) = x + 3, what is [g o f o h](–5)?
to find g(f(h(x))), start with f(h(x)) = 3(x+3)+3 then g(f(h(x))) = 3(3(x+3)+3) + 3
therefore g(f(h(x)))=3(3x+9+3)+3 = 3(3x+12)+3 = 9x+36+3 = 9x+39
Now g(f(h(-5))) = 9(-5)+39 = -45+39 = -6