Answer:
R = 441 ohms
Explanation :
It is given that,
Power of the lamp, P = 100 watts
Voltage, V = 210 volts
The power of an electrical appliance can be written as :
\(P=\dfrac{V^2}{R}\)
\(R=\dfrac{V^2}{P}\)
\(R=\dfrac{(210\ V)^2}{100\ W}\)
R = 441 ohms
So, the resistance of the lamp is 441 ohms
Hence, this is the required solution.