The sides of the rectangle are in the ratio of 4:7. If its length is 31.5 in., find the width, the perimeter, and the area of this rectangle.

Verified Answer :

Let \(\ell\) the length and \(w\) the width. By the ratio of the sides:

\(\dfrac{w}{\ell}=\dfrac{4}{7}\Longrightarrow \dfrac{w}{31.5}=\dfrac{4}{7}\Longrightarrow w=\dfrac{4\cdot31.5}{7}\Longrightarrow \boxed{w=18~in.}\)

Now, we'll find the perimeter p. We'll use the formula below:

\(p=2(\ell+w)\\\\ p=2(31.5+18)\\\\ p=2\cdot49.5\\\\ \boxed{p=99~in.}\)

The area of a rectangle is \(S=w\cdot\ell\). Then:

\(S=w\cdot\ell\\\\ S=18\cdot31.5\\\\ \boxed{S=567~in.^2}\)

Answer:

width=18

Step-by-step explanation:

So im not gonna give you the full everything but you get the width by doing (4/7)31.5  and that equals you answer which in this case is 18