The measure of angle A is 15°, and the length of side BC is 8. What are the lengths of the other two sides, rounded to the nearest tenth?
The triangle is an illustration of right-angled triangles
The other side lengths are (AB) 30.9 and (AC) 29.9
The given parameters are:
\(\mathbf{\angle A = 15^o}\)
\(\mathbf{BC = 8}\)
From the diagram (see attachment), length AC is calculated using the following tangent ratio
\(\mathbf{tan(A) = \frac{BC}{AC}}\)
So, we have:
\(\mathbf{tan(15) = \frac{8}{AC}}\)
Make AC the subject
\(\mathbf{AC = \frac{8}{tan(15)}}\)
\(\mathbf{AC = 29.8564064606}\)
Approximate
\(\mathbf{AC = 29.9}\)
Length AB is calculated using the following sine ratio
\(\mathbf{sin(A) = \frac{BC}{AB}}\)
So, we have:
\(\mathbf{sin(15) = \frac{8}{AB}}\)
Make AB the subject
\(\mathbf{AB = \frac{8}{sin(15)}}\)
\(\mathbf{AB = 30.9096264413}\)
Approximate
\(\mathbf{AB = 30.9}\)
Hence, the other side lengths are (AB) 30.9 and (AC) 29.9
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