The measure of angle A is 15°, and the length of side BC is 8. What are the lengths of the other two sides, rounded to the nearest tenth?

Verified Answer :

AC=29.9
AB=30.9 that is the answer for this question

The triangle is an illustration of right-angled triangles

The other side lengths are (AB) 30.9 and (AC) 29.9

The given parameters are:

\(\mathbf{\angle A = 15^o}\)

\(\mathbf{BC = 8}\)

From the diagram (see attachment), length AC is calculated using the following tangent ratio

\(\mathbf{tan(A) = \frac{BC}{AC}}\)

So, we have:

\(\mathbf{tan(15) = \frac{8}{AC}}\)

Make AC the subject

\(\mathbf{AC = \frac{8}{tan(15)}}\)

\(\mathbf{AC = 29.8564064606}\)

Approximate

\(\mathbf{AC = 29.9}\)

Length AB is calculated using the following sine ratio

\(\mathbf{sin(A) = \frac{BC}{AB}}\)

So, we have:

\(\mathbf{sin(15) = \frac{8}{AB}}\)

Make AB the subject

\(\mathbf{AB = \frac{8}{sin(15)}}\)

\(\mathbf{AB = 30.9096264413}\)

Approximate

\(\mathbf{AB = 30.9}\)

Hence, the other side lengths are (AB) 30.9 and (AC) 29.9

Read more about trigonometry ratios at:

https://brainly.com/question/19597802

View image MrRoyal