Assuming 100% dissociation, calculate the freezing point and boiling point of 3.28 m Na2SO4(aq).

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18-01-2017
Chemistry

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Assuming 100% dissociation, calculate the freezing point and boiling point of 3.28 m Na2SO4(aq).

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MissPhiladelphia MissPhiladelphia · Answer 1 · 2017-01-28T18:56:35-05:00

MissPhiladelphia MissPhiladelphia

28-01-2017

For 100% dissociation:

Freezing point:

Tf sol'n = Tf solvent - (m x kf )

kf for water is -1.86 C/m and Tf for water is 0 C

Tf sol'n = 0 C - (3.28 m x (1.86 C/m))
Tf sol'n = -6.1008 C

Boiling point:

kb for water is 0.512, kb of water is 100 C

Tb sol'n = Tb solvent - (kb x m)
Tb sol'n = 100 + (0.512 x 3.28)
Tb sol'n = 101.68 C

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