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In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9 feet long?

In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9 feet long? class=

Verified Answer :

yashddsy26

so...we can write eqn as

40x = 50(x-1)
so. -10x=-50
so. x=5

therefore .... the distance of 40 lb will be 5 ft ...answer !!!

calculista

Answer:

\(x=5\ ft\)

Step-by-step explanation:

we know that

The bar is \(9\) feet long

so

\(x+(x-1)=9\)

Solve for x

\(2x-1=9\)

\(2x=10\)

\(x=5\ ft\)

Verify

\(40x=50(x-1)\)

substitute the value of x

\(40(5)=50(5-1)\)

\(40(5)=50(4)\)

\(200=200\) -----> the weights are perfectly balanced

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