what is f(x)=3x^2-18x+23 into vertex form
\(3x^2-18x+23=3(x^2-6x)+23=3(x^2-6x+9-9)+23\)\(\quad=3((x-3)^2-9)+23=3(x-3)^2-27+23=3(x-3)^2-4\)The vertex is then \((3,-4)\).