How many more times intense is an earthquake that measures 8 on the Richter scale than an earthquake that measures 5? Explain your answer.

A magnitude 8 earthquake is 108 times more intense than a standard earthquake, while a magnitude 5 earthquake is 105 times more intense than a standard earthquake, and

108 ÷ 105 = 103.

Each unit increase on the Richter scale corresponds to an intensity increase by a factor of 10. So from 5 to 8 on the Richter scale, the intensity increases by 103 = 1,000

Step-by-step explanation:

MrRoyal MrRoyal · Answer 2 · 2022-02-17T08:18:23-05:00

The intensity of the earthquake that measures 8 is 1000 times than an earthquake that measures 5

The intensity from earthquake A to B

The intensities of the earthquakes are calculated using:

\(I = 10^b\)

When the earthquake measures 8, the intensity is:

\(I_1 = 10^8\)

When the earthquake measures 5, the intensity is:

\(I_2 = 10^5\)

The number of times the intensity of the earthquake that measures 8 than an earthquake that measures 5 is:

\(n = \frac{10^8}{10^5}\)

This gives

\(n = 10^3\)

Evaluate

\(n =1000\)

Hence, the intensity of the earthquake that measures 8 is 1000 times than an earthquake that measures 5