What is the value of r in the equation 2(2r + 8) = 3r + 16?
Answer:
The value of r is 0
Step-by-step explanation:
Given the equation 2(2r + 8) = 3r + 16
We have to find the value of r
2(2r + 8) = 3r + 16
By distributive property,
a(b+c)=ab+ac
⇒ 2(2r)+2(8)=3r+16
⇒ 4r+16=3r+16
⇒ 4r-3r=16-16
⇒ r=0
hence, the value of r is 0.