A cylindrical tank with a radius of 10 ft and a height of 40 ft is filled with gasoline. given a density of 670 kg/m 3 , determine the mass (lbm) of the gasoline in the tank.
Cylinder:
V = r² π h
r = 10 ft = 10 0.3048 m = 3.048 m , h = 40 ft = 40 0.3084 = 12.336 m.
Density: m / V = 670 kg/m³
V = 3.048 ² · 3.14 · 12.336 = 359.86 m³
m = V · D = 359.86 m² · 670 kg/m³
Answer:
m = 241,106.4 kg.
Answer:
\(Mass=238,278.8 kg\)
Step-by-step explanation:
Given: radius of cylindrical tank = 10 ft=10×0.3048=3.048m and height of the cylindrical tank=40ft=40×0.3048=12.192m.
Volume of cylindrical tank=\({\pi}r^{2}h\)
=\(3.14(3.048)^2(12.192)\)
=\(3.14(9.290)(12.192)\)
=\(355.64m^3\)
Therefore, the volume of the cylindrical tank=\(355.64m^3\)
Now, We know that Density=\(\frac{Mass}{Volume}\)
⇒\(Mass=Density{\times}volume\)
⇒\(Mass=(670){\times}(355.64)\)
⇒\(Mass=238,278.8 kg\)