How many atoms are in 4.00 moles of helium?
Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles.
4 mol He ( 6.022 x 10^23 atoms / mole ) = 2.4088 x 10^34 atoms He
Answer:
Number of atoms in 4.00 moles of helium = \(2.4092\times 10^{24}\)
Explanation:
Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by \(N_0\).
Avogadro constant:-
\(N_a=6.023\times 10^{23}\)
Thus,
1 mole of helium contains \(6.023\times 10^{23}\) atoms
So,
4.00 moles of helium contains \(4.00\times 6.023\times 10^{23}\) atoms
Number of atoms in 4.00 moles of helium = \(2.4092\times 10^{24}\)