Verified Answer :

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x - the first integer
x+2 - the second integer
x+4 - the third integer

\(x+x+2+x+4=141 \\ 3x+6=141 \\ 3x=141-6 \\ 3x=135 \\ x=\frac{135}{3} \\ x=45 \\ \\ x+2=45+2=47 \\ x+4=45+4=49\)

The integers are: 45, 47, 49.

The integers are: 45, 47, 49.

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