Given f(x) = the quantity of x minus 1, divided by 2, solve for f−1(5). 2 9 11 15
f ( x ) = ( x - 1 ) / 2
y = ( x - 1 ) / 2
x - 1 = 2 y
x = 2 y + 1
f ^(-1) ( x ) = 2 x + 1 ( this is inverse function )
f ^(-1) ( 5 ) = 2 * 5 + 1 = 10 + 1 = 11
Answer: C ) 11
Answer:
\(f^{-1}(5)=11\)
Step-by-step explanation:
Step 1
Find the inverse function
we have
\(f(x)=\frac{x-1}{2}\)
Let
\(y=f(x)\)
\(y=\frac{x-1}{2}\)
Exchanges the variables x for y and y for x
\(x=\frac{y-1}{2}\)
Isolate the variable y
\(y=2x+1\)
Let
\(f^{-1}(x)=y\)
\(f^{-1}(x)=2x+1\) ------> inverse function
Step 2
Find \(f^{-1}(5)\)
Substitute the value of \(x=5\) in the inverse function
\(f^{-1}(5)=2(5)+1=11\)