A big league hitter attacks a fastball! The ball has a mass of 0.16 kg. It is pitched at 38 m/s. After the player hits the ball, it is now traveling 44 m/s in the opposite direction. The impact lasted 0.002 seconds. How big of a force did the ballplayer put on that ball?
The change in momentum of the ball is 0.16 (44 - 38) = 0.96 kg m/s And this should equate to the impulse delivered by a hitting force F t = 0.96 F (0.002) = 0.96 F = 480 N
