Begin with the vertex form of a parabola: \(y=a(x-h)^2+k\) Substitute the values for y = -8, x = 0, h = -1.5, and k = -12.5 We are trying to find the value of a so we will know the equation of the parabola in question. \(-8=a(0-(-1.5))^2-12.5\) \(-8=2.25a-12.5\) \(4.5=2.25a\) \(2=a\) Therefore the equation is: \(y=2(x+1.5)^2-12.5\) Replace y with 0 to find the x-intercepts \(0=2(x+1.5)^2-12.5\) x = 4 and x = -1 Therefore (4,0) and (-1,0) fill in the blanks
