Answer:
The nth term for the arithmetic sequence is given by:
\(a_n = a_1+(n-1)d\) .....[1]
where,
\(a_1\) is the first term.
d is the common difference.
n is the number of terms.
Given the sequence:
3, 5, 7, .......
This is an arithmetic sequence
First term (\(a_1\)) = 3
Common difference(d) = 2
Since,
5-3 = 2,
7-5 = 2 and so o....
We have to find the 30th term of the given sequence:
Substitute n = 30 and the given values in [1] we have;
\(a_{30} = 3+(30-1)(2)\)
\(a_{30} = 3+29 \cdot 2 = 3+58 = 61\)
Therefore, the 30th term of the given sequence is, 61
