What are the coordinates of the turning point for the function f(x) = (x+3)^3 + 1
The turning point is just the minimum/maximum so the coordinates are (-3,1) which you find from the expression of (x+3)³ + 1
Answer:
The turning points for the given function is (-3,1).
Step-by-step explanation:
The given function is
\(f(x)=(x+3)^3+1\)
The turning point of a function where the \(f'(x)=0\).
\(f'(x)=3(x+3)^2\)
Equate the first derivative equals to 0.
\(0=3(x+3)^2\)
\(x+3=0\)
\(x=-3\)
At the turning point the x-coordinate is -3.
Substitute x=-3 in the given function.
\(f(-3)=(-3+3)^3+1\)
\(f(-3)=1\)
At the turning point the y-coordinate is 1.
Therefore the turning point is (-3,1).