moles is equal to mass over molar mass
122g/25.94 (25.94 is the molar mass of LiF)
3 = (4.703/L)
L = 1.567
1.567 L is the volume of a 3.00M(mol/L) solution made with 122g of LiF.
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.
\(Molality = \frac{Moles \;solute}{Solvent \;in \;kg}\)
Firstly calculate the moles of LiF.
Moles = \(\frac{mass}{molar \;mass}\)
Moles = \(\frac{122g}{25.94}\). (25.94 is the molar mass of LiF)
Moles = 4.703
Now find the volume:
\(Molarity = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}\)
\(3.00M = \frac{4.703}{Volume \;of \;solution \;in \;litre}\)
V = 1.567 L
Hence, 1.567 L is the volume of a 3.00M(mol/L) solution made with 122g of LiF.
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